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4x-2=x^2-3x
We move all terms to the left:
4x-2-(x^2-3x)=0
We get rid of parentheses
-x^2+4x+3x-2=0
We add all the numbers together, and all the variables
-1x^2+7x-2=0
a = -1; b = 7; c = -2;
Δ = b2-4ac
Δ = 72-4·(-1)·(-2)
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{41}}{2*-1}=\frac{-7-\sqrt{41}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{41}}{2*-1}=\frac{-7+\sqrt{41}}{-2} $
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